Talk:Ragged holes

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You can't really use CEP(p) since you have no idea of what percentage of holes you'll be able to find if you shoot another target.

Consider this situation. You make 100 shots. There are enough shots for which a position can be determined so that you can estimate the group center. Now you count how many shots you can find (say 30). Take half of that number-15. Now use CEP(85). Sounds good right? Dah... How many different circles can you draw that eliminate 15 of the holes? A lot. It would conceivable to find all such circles and take average position and size. Not possible work for a human, but a computer doesn't care.

If done right ragged hole measurements aren't crippling.

Herb (talk) 18:12, 1 June 2015 (EDT)